A box contains some pomegranates, kiwis and starfruits. 0.4 of the pomegranates is equal to 70% of the kiwis. The number of starfruits is ⁵₆ of the total number of kiwis and pomegranates. If there are 341 less kiwis than starfruits, how many fruits are there in the box altogether?

Pomegranates	Kiwis	Starfruits
7x6	4x6
6x11		5x11
42 u	24 u	55 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the pomegranates is equal to 70% of the kiwis. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the pomegranates = 7x210x2 of the kiwis
1435 of the pomegranates = 1420 of the kiwis 

Pomegranates : Kiwis
35 : 20 _(÷5)
7 : 4

The total number of pomegranates and kiwis is repeated.  Make the total number of pomegranates and kiwis the same.  LCM of 11 and 6 is 66.

Number of less kiwis than starfruits
= 55 u - 24 u
= 31 u

31 u = 341

1 u = 341 ÷ 31 = 11

Number of the fruits in the box altogether
= 42 u + 24 u + 55 u
= 121 u
= 121 x 11
= 1331

Answer(s): 1331