A box contains some pears, persimmons and lemons. 0.6 of the pears is equal to 80% of the persimmons. The number of lemons is ³₅ of the total number of persimmons and pears. If there are 54 more lemons than persimmons, how many fruits are there in the box altogether?

Pears	Persimmons	Lemons
4x5	3x5
5x7		3x7
20 u	15 u	21 u

0.6 = ⁶₁₀= ³₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.6 of the pears is equal to 80% of the persimmons. Make the numerators the same.  LCM of 3 and 4 is 12.

3x45x4 of the pears = 4x35x3 of the persimmons
1220 of the pears = 1215 of the persimmons 

Pears : Persimmons
20 : 15 _(÷5)
4 : 3

The total number of pears and persimmons is repeated.  Make the total number of pears and persimmons the same.  LCM of 7 and 5 is 35.

Number of more lemons than persimmons
= 21 u - 15 u
= 6 u

6 u = 54

1 u = 54 ÷ 6 = 9

Number of the fruits in the box altogether
= 20 u + 15 u + 21 u
= 56 u
= 56 x 9
= 504

Answer(s): 504