A box contains some mangosteens, oranges and chikoos. 0.4 of the mangosteens is equal to 60% of the oranges. The number of chikoos is
57 of the total number of oranges and mangosteens. If there are 22 more chikoos than oranges, how many fruits are there in the box altogether?
Mangosteens |
Oranges |
Chikoos |
3x7 |
2x7 |
|
7x5 |
5x5 |
21 u |
14 u |
25 u |
0.4 =
410=
25 60% =
60100 =
35 0.4 of the mangosteens is equal to 60% of the oranges. Make the numerators the same. LCM of 2 and 3 is 6.
2x35x3 of the mangosteens =
3x25x2 of the oranges
615 of the mangosteens =
610 of the oranges
Mangosteens : Oranges
15 : 10
(÷5)
3 : 2
The total number of mangosteens and oranges is repeated. Make the total number of mangosteens and oranges the same. LCM of 5 and 7 is 35.
Number of more chikoos than oranges
= 25 u - 14 u
= 11 u
11 u = 22
1 u = 22 ÷ 11 = 2
Number of the fruits in the box altogether
= 21 u + 14 u + 25 u
= 60 u
= 60 x 2
= 120
Answer(s): 120