A container contains some pears, mangoes and persimmons. 0.2 of the pears is equal to 70% of the mangoes. The number of persimmons is ⁵₇ of the total number of mangoes and pears. If there are 372 less mangoes than persimmons, how many fruits are there in the container altogether?

Pears	Mangoes	Persimmons
7x7	2x7
7x9		5x9
49 u	14 u	45 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the pears is equal to 70% of the mangoes. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the pears = 7x110x1 of the mangoes
735 of the pears = 710 of the mangoes 

Pears : Mangoes
35 : 10 _(÷5)
7 : 2

The total number of pears and mangoes is repeated.  Make the total number of pears and mangoes the same.  LCM of 9 and 7 is 63.

Number of less mangoes than persimmons
= 45 u - 14 u
= 31 u

31 u = 372

1 u = 372 ÷ 31 = 12

Number of the fruits in the container altogether
= 49 u + 14 u + 45 u
= 108 u
= 108 x 12
= 1296

Answer(s): 1296