A box contains some lemons, oranges and pears. 0.4 of the lemons is equal to 60% of the oranges. The number of pears is ³₄ of the total number of oranges and lemons. If there are 49 more pears than oranges, how many fruits are there in the box altogether?

Lemons	Oranges	Pears
3x4	2x4
4x5		3x5
12 u	8 u	15 u

0.4 = ⁴₁₀= ²₅
60% = ⁶⁰₁₀₀ = ³₅

0.4 of the lemons is equal to 60% of the oranges. Make the numerators the same.  LCM of 2 and 3 is 6.

2x35x3 of the lemons = 3x25x2 of the oranges
615 of the lemons = 610 of the oranges 

Lemons : Oranges
15 : 10 _(÷5)
3 : 2

The total number of lemons and oranges is repeated.  Make the total number of lemons and oranges the same.  LCM of 5 and 4 is 20.

Number of more pears than oranges
= 15 u - 8 u
= 7 u

7 u = 49

1 u = 49 ÷ 7 = 7

Number of the fruits in the box altogether
= 12 u + 8 u + 15 u
= 35 u
= 35 x 7
= 245

Answer(s): 245