A container contains some kiwis, chikoos and oranges. 0.6 of the kiwis is equal to 70% of the chikoos. The number of oranges is ⁵₈ of the total number of chikoos and kiwis. If there are 187 more oranges than chikoos, how many fruits are there in the container altogether?

Kiwis	Chikoos	Oranges
7x8	6x8
8x13		5x13
56 u	48 u	65 u

0.6 = ⁶₁₀= ³₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.6 of the kiwis is equal to 70% of the chikoos. Make the numerators the same.  LCM of 3 and 7 is 21.

3x75x7 of the kiwis = 7x310x3 of the chikoos
2135 of the kiwis = 2130 of the chikoos 

Kiwis : Chikoos
35 : 30 _(÷5)
7 : 6

The total number of kiwis and chikoos is repeated.  Make the total number of kiwis and chikoos the same.  LCM of 13 and 8 is 104.

Number of more oranges than chikoos
= 65 u - 48 u
= 17 u

17 u = 187

1 u = 187 ÷ 17 = 11

Number of the fruits in the container altogether
= 56 u + 48 u + 65 u
= 169 u
= 169 x 11
= 1859

Answer(s): 1859