A container contains some oranges, lemons and kiwis. 0.4 of the oranges is equal to 80% of the lemons. The number of kiwis is ⁴₅ of the total number of lemons and oranges. If there are 70 more kiwis than lemons, how many fruits are there in the container altogether?

Oranges	Lemons	Kiwis
2x5	1x5
5x3		4x3
10 u	5 u	12 u

0.4 = ⁴₁₀= ²₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.4 of the oranges is equal to 80% of the lemons. Make the numerators the same.  LCM of 2 and 4 is 4.

2x25x2 of the oranges = 4x15x1 of the lemons
410 of the oranges = 45 of the lemons 

Oranges : Lemons
10 : 5 _(÷5)
2 : 1

The total number of oranges and lemons is repeated.  Make the total number of oranges and lemons the same.  LCM of 3 and 5 is 15.

Number of more kiwis than lemons
= 12 u - 5 u
= 7 u

7 u = 70

1 u = 70 ÷ 7 = 10

Number of the fruits in the container altogether
= 10 u + 5 u + 12 u
= 27 u
= 27 x 10
= 270

Answer(s): 270