A box contains some kiwis, starfruits and pomegranates. 0.2 of the kiwis is equal to 80% of the starfruits. The number of pomegranates is
12 of the total number of starfruits and kiwis. If there are 6 more pomegranates than starfruits, how many fruits are there in the box altogether?
Kiwis |
Starfruits |
Pomegranates |
4x2 |
1x2 |
|
2x5 |
1x5 |
8 u |
2 u |
5 u |
0.2 =
210=
15 80% =
80100 =
45 0.2 of the kiwis is equal to 80% of the starfruits. Make the numerators the same. LCM of 1 and 4 is 4.
1x45x4 of the kiwis =
4x15x1 of the starfruits
420 of the kiwis =
45 of the starfruits
Kiwis : Starfruits
20 : 5
(÷5)
4 : 1
The total number of kiwis and starfruits is repeated. Make the total number of kiwis and starfruits the same. LCM of 5 and 2 is 10.
Number of more pomegranates than starfruits
= 5 u - 2 u
= 3 u
3 u = 6
1 u = 6 ÷ 3 = 2
Number of the fruits in the box altogether
= 8 u + 2 u + 5 u
= 15 u
= 15 x 2
= 30
Answer(s): 30