A box contains some oranges, kiwis and apples. 0.4 of the oranges is equal to 70% of the kiwis. The number of apples is ³₇ of the total number of kiwis and oranges. If there are 10 more apples than kiwis, how many fruits are there in the box altogether?

Oranges	Kiwis	Apples
7x7	4x7
7x11		3x11
49 u	28 u	33 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the oranges is equal to 70% of the kiwis. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the oranges = 7x210x2 of the kiwis
1435 of the oranges = 1420 of the kiwis 

Oranges : Kiwis
35 : 20 _(÷5)
7 : 4

The total number of oranges and kiwis is repeated.  Make the total number of oranges and kiwis the same.  LCM of 11 and 7 is 77.

Number of more apples than kiwis
= 33 u - 28 u
= 5 u

5 u = 10

1 u = 10 ÷ 5 = 2

Number of the fruits in the box altogether
= 49 u + 28 u + 33 u
= 110 u
= 110 x 2
= 220

Answer(s): 220