A box contains some pears, chikoos and oranges. 0.2 of the pears is equal to 70% of the chikoos. The number of oranges is ⁵₇ of the total number of chikoos and pears. If there are 372 less chikoos than oranges, how many fruits are there in the box altogether?

Pears	Chikoos	Oranges
7x7	2x7
7x9		5x9
49 u	14 u	45 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the pears is equal to 70% of the chikoos. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the pears = 7x110x1 of the chikoos
735 of the pears = 710 of the chikoos 

Pears : Chikoos
35 : 10 _(÷5)
7 : 2

The total number of pears and chikoos is repeated.  Make the total number of pears and chikoos the same.  LCM of 9 and 7 is 63.

Number of less chikoos than oranges
= 45 u - 14 u
= 31 u

31 u = 372

1 u = 372 ÷ 31 = 12

Number of the fruits in the box altogether
= 49 u + 14 u + 45 u
= 108 u
= 108 x 12
= 1296

Answer(s): 1296