A box contains some chikoos, persimmons and pears. 0.2 of the chikoos is equal to 60% of the persimmons. The number of pears is ⁵₈ of the total number of persimmons and chikoos. If there are 18 more pears than persimmons, how many fruits are there in the box altogether?

Chikoos	Persimmons	Pears
3x2	1x2
8x1		5x1
6 u	2 u	5 u

0.2 = ²₁₀= ¹₅
60% = ⁶⁰₁₀₀ = ³₅

0.2 of the chikoos is equal to 60% of the persimmons. Make the numerators the same.  LCM of 1 and 3 is 3.

1x35x3 of the chikoos = 3x15x1 of the persimmons
315 of the chikoos = 35 of the persimmons 

Chikoos : Persimmons
15 : 5 _(÷5)
3 : 1

The total number of chikoos and persimmons is repeated.  Make the total number of chikoos and persimmons the same.  LCM of 4 and 8 is 8.

Number of more pears than persimmons
= 5 u - 2 u
= 3 u

3 u = 18

1 u = 18 ÷ 3 = 6

Number of the fruits in the box altogether
= 6 u + 2 u + 5 u
= 13 u
= 13 x 6
= 78

Answer(s): 78