A box contains some pomegranates, lemons and oranges. 0.2 of the pomegranates is equal to 80% of the lemons. The number of oranges is
57 of the total number of lemons and pomegranates. If there are 126 more oranges than lemons, how many fruits are there in the box altogether?
Pomegranates |
Lemons |
Oranges |
4x7 |
1x7 |
|
7x5 |
5x5 |
28 u |
7 u |
25 u |
0.2 =
210=
15 80% =
80100 =
45 0.2 of the pomegranates is equal to 80% of the lemons. Make the numerators the same. LCM of 1 and 4 is 4.
1x45x4 of the pomegranates =
4x15x1 of the lemons
420 of the pomegranates =
45 of the lemons
Pomegranates : Lemons
20 : 5
(÷5)
4 : 1
The total number of pomegranates and lemons is repeated. Make the total number of pomegranates and lemons the same. LCM of 5 and 7 is 35.
Number of more oranges than lemons
= 25 u - 7 u
= 18 u
18 u = 126
1 u = 126 ÷ 18 = 7
Number of the fruits in the box altogether
= 28 u + 7 u + 25 u
= 60 u
= 60 x 7
= 420
Answer(s): 420