A container contains some kiwis, pomegranates and lemons. 0.2 of the kiwis is equal to 80% of the pomegranates. The number of lemons is
13 of the total number of pomegranates and kiwis. If there are 12 more lemons than pomegranates, how many fruits are there in the container altogether?
Kiwis |
Pomegranates |
Lemons |
4x3 |
1x3 |
|
3x5 |
1x5 |
12 u |
3 u |
5 u |
0.2 =
210=
15 80% =
80100 =
45 0.2 of the kiwis is equal to 80% of the pomegranates. Make the numerators the same. LCM of 1 and 4 is 4.
1x45x4 of the kiwis =
4x15x1 of the pomegranates
420 of the kiwis =
45 of the pomegranates
Kiwis : Pomegranates
20 : 5
(÷5)
4 : 1
The total number of kiwis and pomegranates is repeated. Make the total number of kiwis and pomegranates the same. LCM of 5 and 3 is 15.
Number of more lemons than pomegranates
= 5 u - 3 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of the fruits in the container altogether
= 12 u + 3 u + 5 u
= 20 u
= 20 x 6
= 120
Answer(s): 120