A container contains some oranges, persimmons and pears. 0.2 of the oranges is equal to 60% of the persimmons. The number of pears is ⁵₈ of the total number of persimmons and oranges. If there are 33 more pears than persimmons, how many fruits are there in the container altogether?

Oranges	Persimmons	Pears
3x2	1x2
8x1		5x1
6 u	2 u	5 u

0.2 = ²₁₀= ¹₅
60% = ⁶⁰₁₀₀ = ³₅

0.2 of the oranges is equal to 60% of the persimmons. Make the numerators the same.  LCM of 1 and 3 is 3.

1x35x3 of the oranges = 3x15x1 of the persimmons
315 of the oranges = 35 of the persimmons 

Oranges : Persimmons
15 : 5 _(÷5)
3 : 1

The total number of oranges and persimmons is repeated.  Make the total number of oranges and persimmons the same.  LCM of 4 and 8 is 8.

Number of more pears than persimmons
= 5 u - 2 u
= 3 u

3 u = 33

1 u = 33 ÷ 3 = 11

Number of the fruits in the container altogether
= 6 u + 2 u + 5 u
= 13 u
= 13 x 11
= 143

Answer(s): 143