A box contains some kiwis, chikoos and mangoes. 0.8 of the kiwis is equal to 70% of the chikoos. The number of mangoes is ⁵₈ of the total number of chikoos and kiwis. If there are 33 less chikoos than mangoes, how many fruits are there in the box altogether?

Kiwis	Chikoos	Mangoes
7x8	8x8
8x15		5x15
56 u	64 u	75 u

0.8 = ⁸₁₀= ⁴₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.8 of the kiwis is equal to 70% of the chikoos. Make the numerators the same.  LCM of 4 and 7 is 28.

4x75x7 of the kiwis = 7x410x4 of the chikoos
2835 of the kiwis = 2840 of the chikoos 

Kiwis : Chikoos
35 : 40 _(÷5)
7 : 8

The total number of kiwis and chikoos is repeated.  Make the total number of kiwis and chikoos the same.  LCM of 15 and 8 is 120.

Number of less chikoos than mangoes
= 75 u - 64 u
= 11 u

11 u = 33

1 u = 33 ÷ 11 = 3

Number of the fruits in the box altogether
= 56 u + 64 u + 75 u
= 195 u
= 195 x 3
= 585

Answer(s): 585