A container contains some kiwis, lemons and oranges. 0.2 of the kiwis is equal to 40% of the lemons. The number of oranges is ⁴₅ of the total number of lemons and kiwis. If there are 28 more oranges than lemons, how many fruits are there in the container altogether?

Kiwis	Lemons	Oranges
2x5	1x5
5x3		4x3
10 u	5 u	12 u

0.2 = ²₁₀= ¹₅
40% = ⁴⁰₁₀₀ = ²₅

0.2 of the kiwis is equal to 40% of the lemons. Make the numerators the same.  LCM of 1 and 2 is 2.

1x25x2 of the kiwis = 2x15x1 of the lemons
210 of the kiwis = 25 of the lemons 

Kiwis : Lemons
10 : 5 _(÷5)
2 : 1

The total number of kiwis and lemons is repeated.  Make the total number of kiwis and lemons the same.  LCM of 3 and 5 is 15.

Number of more oranges than lemons
= 12 u - 5 u
= 7 u

7 u = 28

1 u = 28 ÷ 7 = 4

Number of the fruits in the container altogether
= 10 u + 5 u + 12 u
= 27 u
= 27 x 4
= 108

Answer(s): 108