A container contains some pomegranates, mangoes and kiwis. 0.4 of the pomegranates is equal to 70% of the mangoes. The number of kiwis is
23 of the total number of mangoes and pomegranates. If there are 40 less mangoes than kiwis, how many fruits are there in the container altogether?
Pomegranates |
Mangoes |
Kiwis |
7x3 |
4x3 |
|
3x11 |
2x11 |
21 u |
12 u |
22 u |
0.4 =
410=
25 70% =
70100 =
710 0.4 of the pomegranates is equal to 70% of the mangoes. Make the numerators the same. LCM of 2 and 7 is 14.
2x75x7 of the pomegranates =
7x210x2 of the mangoes
1435 of the pomegranates =
1420 of the mangoes
Pomegranates : Mangoes
35 : 20
(÷5)
7 : 4
The total number of pomegranates and mangoes is repeated. Make the total number of pomegranates and mangoes the same. LCM of 11 and 3 is 33.
Number of less mangoes than kiwis
= 22 u - 12 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of the fruits in the container altogether
= 21 u + 12 u + 22 u
= 55 u
= 55 x 4
= 220
Answer(s): 220