A box contains some oranges, kiwis and mangoes. 0.4 of the oranges is equal to 60% of the kiwis. The number of mangoes is ⁴₇ of the total number of kiwis and oranges. If there are 36 less kiwis than mangoes, how many fruits are there in the box altogether?

Oranges	Kiwis	Mangoes
3x7	2x7
7x5		4x5
21 u	14 u	20 u

0.4 = ⁴₁₀= ²₅
60% = ⁶⁰₁₀₀ = ³₅

0.4 of the oranges is equal to 60% of the kiwis. Make the numerators the same.  LCM of 2 and 3 is 6.

2x35x3 of the oranges = 3x25x2 of the kiwis
615 of the oranges = 610 of the kiwis 

Oranges : Kiwis
15 : 10 _(÷5)
3 : 2

The total number of oranges and kiwis is repeated.  Make the total number of oranges and kiwis the same.  LCM of 5 and 7 is 35.

Number of less kiwis than mangoes
= 20 u - 14 u
= 6 u

6 u = 36

1 u = 36 ÷ 6 = 6

Number of the fruits in the box altogether
= 21 u + 14 u + 20 u
= 55 u
= 55 x 6
= 330

Answer(s): 330