A container contains some kiwis, mangosteens and oranges. 0.8 of the kiwis is equal to 60% of the mangosteens. The number of oranges is ⁵₈ of the total number of mangosteens and kiwis. If there are 6 more oranges than mangosteens, how many fruits are there in the container altogether?

Kiwis	Mangosteens	Oranges
3x8	4x8
8x7		5x7
24 u	32 u	35 u

0.8 = ⁸₁₀= ⁴₅
60% = ⁶⁰₁₀₀ = ³₅

0.8 of the kiwis is equal to 60% of the mangosteens. Make the numerators the same.  LCM of 4 and 3 is 12.

4x35x3 of the kiwis = 3x45x4 of the mangosteens
1215 of the kiwis = 1220 of the mangosteens 

Kiwis : Mangosteens
15 : 20 _(÷5)
3 : 4

The total number of kiwis and mangosteens is repeated.  Make the total number of kiwis and mangosteens the same.  LCM of 7 and 8 is 56.

Number of more oranges than mangosteens
= 35 u - 32 u
= 3 u

3 u = 6

1 u = 6 ÷ 3 = 2

Number of the fruits in the container altogether
= 24 u + 32 u + 35 u
= 91 u
= 91 x 2
= 182

Answer(s): 182