A box contains some mangosteens, kiwis and oranges. 0.2 of the mangosteens is equal to 60% of the kiwis. The number of oranges is
37 of the total number of kiwis and mangosteens. If there are 35 more oranges than kiwis, how many fruits are there in the box altogether?
Mangosteens |
Kiwis |
Oranges |
3x7 |
1x7 |
|
7x4 |
3x4 |
21 u |
7 u |
12 u |
0.2 =
210=
15 60% =
60100 =
35 0.2 of the mangosteens is equal to 60% of the kiwis. Make the numerators the same. LCM of 1 and 3 is 3.
1x35x3 of the mangosteens =
3x15x1 of the kiwis
315 of the mangosteens =
35 of the kiwis
Mangosteens : Kiwis
15 : 5
(÷5)
3 : 1
The total number of mangosteens and kiwis is repeated. Make the total number of mangosteens and kiwis the same. LCM of 4 and 7 is 28.
Number of more oranges than kiwis
= 12 u - 7 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of the fruits in the box altogether
= 21 u + 7 u + 12 u
= 40 u
= 40 x 7
= 280
Answer(s): 280