A container contains some mangosteens, persimmons and mangoes. 0.2 of the mangosteens is equal to 70% of the persimmons. The number of mangoes is ³₇ of the total number of persimmons and mangosteens. If there are 117 more mangoes than persimmons, how many fruits are there in the container altogether?

Mangosteens	Persimmons	Mangoes
7x7	2x7
7x9		3x9
49 u	14 u	27 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the mangosteens is equal to 70% of the persimmons. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the mangosteens = 7x110x1 of the persimmons
735 of the mangosteens = 710 of the persimmons 

Mangosteens : Persimmons
35 : 10 _(÷5)
7 : 2

The total number of mangosteens and persimmons is repeated.  Make the total number of mangosteens and persimmons the same.  LCM of 9 and 7 is 63.

Number of more mangoes than persimmons
= 27 u - 14 u
= 13 u

13 u = 117

1 u = 117 ÷ 13 = 9

Number of the fruits in the container altogether
= 49 u + 14 u + 27 u
= 90 u
= 90 x 9
= 810

Answer(s): 810