A box contains some pears, mangosteens and kiwis. 0.6 of the pears is equal to 70% of the mangosteens. The number of kiwis is ²₃ of the total number of mangosteens and pears. If there are 56 less mangosteens than kiwis, how many fruits are there in the box altogether?

Pears	Mangosteens	Kiwis
7x3	6x3
3x13		2x13
21 u	18 u	26 u

0.6 = ⁶₁₀= ³₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.6 of the pears is equal to 70% of the mangosteens. Make the numerators the same.  LCM of 3 and 7 is 21.

3x75x7 of the pears = 7x310x3 of the mangosteens
2135 of the pears = 2130 of the mangosteens 

Pears : Mangosteens
35 : 30 _(÷5)
7 : 6

The total number of pears and mangosteens is repeated.  Make the total number of pears and mangosteens the same.  LCM of 13 and 3 is 39.

Number of less mangosteens than kiwis
= 26 u - 18 u
= 8 u

8 u = 56

1 u = 56 ÷ 8 = 7

Number of the fruits in the box altogether
= 21 u + 18 u + 26 u
= 65 u
= 65 x 7
= 455

Answer(s): 455