A box contains some oranges, persimmons and mangosteens. 0.2 of the oranges is equal to 30% of the persimmons. The number of mangosteens is
56 of the total number of persimmons and oranges. If there are 39 less persimmons than mangosteens, how many fruits are there in the box altogether?
Oranges |
Persimmons |
Mangosteens |
3x6 |
2x6 |
|
6x5 |
5x5 |
18 u |
12 u |
25 u |
0.2 =
210=
15 30% =
30100 =
310 0.2 of the oranges is equal to 30% of the persimmons. Make the numerators the same. LCM of 1 and 3 is 3.
1x35x3 of the oranges =
3x110x1 of the persimmons
315 of the oranges =
310 of the persimmons
Oranges : Persimmons
15 : 10
(÷5)
3 : 2
The total number of oranges and persimmons is repeated. Make the total number of oranges and persimmons the same. LCM of 5 and 6 is 30.
Number of less persimmons than mangosteens
= 25 u - 12 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Number of the fruits in the box altogether
= 18 u + 12 u + 25 u
= 55 u
= 55 x 3
= 165
Answer(s): 165