A container contains some mangoes, mangosteens and kiwis. 0.2 of the mangoes is equal to 70% of the mangosteens. The number of kiwis is ⁴₇ of the total number of mangosteens and mangoes. If there are 110 more kiwis than mangosteens, how many fruits are there in the container altogether?

Mangoes	Mangosteens	Kiwis
7x7	2x7
7x9		4x9
49 u	14 u	36 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the mangoes is equal to 70% of the mangosteens. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the mangoes = 7x110x1 of the mangosteens
735 of the mangoes = 710 of the mangosteens 

Mangoes : Mangosteens
35 : 10 _(÷5)
7 : 2

The total number of mangoes and mangosteens is repeated.  Make the total number of mangoes and mangosteens the same.  LCM of 9 and 7 is 63.

Number of more kiwis than mangosteens
= 36 u - 14 u
= 22 u

22 u = 110

1 u = 110 ÷ 22 = 5

Number of the fruits in the container altogether
= 49 u + 14 u + 36 u
= 99 u
= 99 x 5
= 495

Answer(s): 495