A container contains some apples, persimmons and pears. 0.8 of the apples is equal to 60% of the persimmons. The number of pears is
45 of the total number of persimmons and apples. If there are 24 more pears than persimmons, how many fruits are there in the container altogether?
Apples |
Persimmons |
Pears |
3x5 |
4x5 |
|
5x7 |
4x7 |
15 u |
20 u |
28 u |
0.8 =
810=
45 60% =
60100 =
35 0.8 of the apples is equal to 60% of the persimmons. Make the numerators the same. LCM of 4 and 3 is 12.
4x35x3 of the apples =
3x45x4 of the persimmons
1215 of the apples =
1220 of the persimmons
Apples : Persimmons
15 : 20
(÷5)
3 : 4
The total number of apples and persimmons is repeated. Make the total number of apples and persimmons the same. LCM of 7 and 5 is 35.
Number of more pears than persimmons
= 28 u - 20 u
= 8 u
8 u = 24
1 u = 24 ÷ 8 = 3
Number of the fruits in the container altogether
= 15 u + 20 u + 28 u
= 63 u
= 63 x 3
= 189
Answer(s): 189