A container contains some oranges, chikoos and pears. 0.8 of the oranges is equal to 70% of the chikoos. The number of pears is ²₃ of the total number of chikoos and oranges. If there are 18 more pears than chikoos, how many fruits are there in the container altogether?

Oranges	Chikoos	Pears
7x1	8x1
3x5		2x5
7 u	8 u	10 u

0.8 = ⁸₁₀= ⁴₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.8 of the oranges is equal to 70% of the chikoos. Make the numerators the same.  LCM of 4 and 7 is 28.

4x75x7 of the oranges = 7x410x4 of the chikoos
2835 of the oranges = 2840 of the chikoos 

Oranges : Chikoos
35 : 40 _(÷5)
7 : 8

The total number of oranges and chikoos is repeated.  Make the total number of oranges and chikoos the same.  LCM of 15 and 3 is 15.

Number of more pears than chikoos
= 10 u - 8 u
= 2 u

2 u = 18

1 u = 18 ÷ 2 = 9

Number of the fruits in the container altogether
= 7 u + 8 u + 10 u
= 25 u
= 25 x 9
= 225

Answer(s): 225