A box contains some chikoos, starfruits and persimmons. 0.4 of the chikoos is equal to 60% of the starfruits. The number of persimmons is ⁵₆ of the total number of starfruits and chikoos. If there are 91 less starfruits than persimmons, how many fruits are there in the box altogether?

Chikoos	Starfruits	Persimmons
3x6	2x6
6x5		5x5
18 u	12 u	25 u

0.4 = ⁴₁₀= ²₅
60% = ⁶⁰₁₀₀ = ³₅

0.4 of the chikoos is equal to 60% of the starfruits. Make the numerators the same.  LCM of 2 and 3 is 6.

2x35x3 of the chikoos = 3x25x2 of the starfruits
615 of the chikoos = 610 of the starfruits 

Chikoos : Starfruits
15 : 10 _(÷5)
3 : 2

The total number of chikoos and starfruits is repeated.  Make the total number of chikoos and starfruits the same.  LCM of 5 and 6 is 30.

Number of less starfruits than persimmons
= 25 u - 12 u
= 13 u

13 u = 91

1 u = 91 ÷ 13 = 7

Number of the fruits in the box altogether
= 18 u + 12 u + 25 u
= 55 u
= 55 x 7
= 385

Answer(s): 385