A box contains some pomegranates, mangoes and kiwis. 0.4 of the pomegranates is equal to 80% of the mangoes. The number of kiwis is
45 of the total number of mangoes and pomegranates. If there are 14 more kiwis than mangoes, how many fruits are there in the box altogether?
Pomegranates |
Mangoes |
Kiwis |
2x5 |
1x5 |
|
5x3 |
4x3 |
10 u |
5 u |
12 u |
0.4 =
410=
25 80% =
80100 =
45 0.4 of the pomegranates is equal to 80% of the mangoes. Make the numerators the same. LCM of 2 and 4 is 4.
2x25x2 of the pomegranates =
4x15x1 of the mangoes
410 of the pomegranates =
45 of the mangoes
Pomegranates : Mangoes
10 : 5
(÷5)
2 : 1
The total number of pomegranates and mangoes is repeated. Make the total number of pomegranates and mangoes the same. LCM of 3 and 5 is 15.
Number of more kiwis than mangoes
= 12 u - 5 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of the fruits in the box altogether
= 10 u + 5 u + 12 u
= 27 u
= 27 x 2
= 54
Answer(s): 54