A container contains some chikoos, pears and persimmons. 0.4 of the chikoos is equal to 70% of the pears. The number of persimmons is
45 of the total number of pears and chikoos. If there are 264 more persimmons than pears, how many fruits are there in the container altogether?
Chikoos |
Pears |
Persimmons |
7x5 |
4x5 |
|
5x11 |
4x11 |
35 u |
20 u |
44 u |
0.4 =
410=
25 70% =
70100 =
710 0.4 of the chikoos is equal to 70% of the pears. Make the numerators the same. LCM of 2 and 7 is 14.
2x75x7 of the chikoos =
7x210x2 of the pears
1435 of the chikoos =
1420 of the pears
Chikoos : Pears
35 : 20
(÷5)
7 : 4
The total number of chikoos and pears is repeated. Make the total number of chikoos and pears the same. LCM of 11 and 5 is 55.
Number of more persimmons than pears
= 44 u - 20 u
= 24 u
24 u = 264
1 u = 264 ÷ 24 = 11
Number of the fruits in the container altogether
= 35 u + 20 u + 44 u
= 99 u
= 99 x 11
= 1089
Answer(s): 1089