A container contains some mangoes, persimmons and pomegranates. 0.2 of the mangoes is equal to 40% of the persimmons. The number of pomegranates is ⁴₅ of the total number of persimmons and mangoes. If there are 63 less persimmons than pomegranates, how many fruits are there in the container altogether?

Mangoes	Persimmons	Pomegranates
2x5	1x5
5x3		4x3
10 u	5 u	12 u

0.2 = ²₁₀= ¹₅
40% = ⁴⁰₁₀₀ = ²₅

0.2 of the mangoes is equal to 40% of the persimmons. Make the numerators the same.  LCM of 1 and 2 is 2.

1x25x2 of the mangoes = 2x15x1 of the persimmons
210 of the mangoes = 25 of the persimmons 

Mangoes : Persimmons
10 : 5 _(÷5)
2 : 1

The total number of mangoes and persimmons is repeated.  Make the total number of mangoes and persimmons the same.  LCM of 3 and 5 is 15.

Number of less persimmons than pomegranates
= 12 u - 5 u
= 7 u

7 u = 63

1 u = 63 ÷ 7 = 9

Number of the fruits in the container altogether
= 10 u + 5 u + 12 u
= 27 u
= 27 x 9
= 243

Answer(s): 243