A container contains some pears, mangoes and kiwis. 0.8 of the pears is equal to 70% of the mangoes. The number of kiwis is ⁵₆ of the total number of mangoes and pears. If there are 63 less mangoes than kiwis, how many fruits are there in the container altogether?

Pears	Mangoes	Kiwis
7x2	8x2
6x5		5x5
14 u	16 u	25 u

0.8 = ⁸₁₀= ⁴₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.8 of the pears is equal to 70% of the mangoes. Make the numerators the same.  LCM of 4 and 7 is 28.

4x75x7 of the pears = 7x410x4 of the mangoes
2835 of the pears = 2840 of the mangoes 

Pears : Mangoes
35 : 40 _(÷5)
7 : 8

The total number of pears and mangoes is repeated.  Make the total number of pears and mangoes the same.  LCM of 15 and 6 is 30.

Number of less mangoes than kiwis
= 25 u - 16 u
= 9 u

9 u = 63

1 u = 63 ÷ 9 = 7

Number of the fruits in the container altogether
= 14 u + 16 u + 25 u
= 55 u
= 55 x 7
= 385

Answer(s): 385