A box contains some oranges, persimmons and pomegranates. 0.2 of the oranges is equal to 40% of the persimmons. The number of pomegranates is
34 of the total number of persimmons and oranges. If there are 60 more pomegranates than persimmons, how many fruits are there in the box altogether?
Oranges |
Persimmons |
Pomegranates |
2x4 |
1x4 |
|
4x3 |
3x3 |
8 u |
4 u |
9 u |
0.2 =
210=
15 40% =
40100 =
25 0.2 of the oranges is equal to 40% of the persimmons. Make the numerators the same. LCM of 1 and 2 is 2.
1x25x2 of the oranges =
2x15x1 of the persimmons
210 of the oranges =
25 of the persimmons
Oranges : Persimmons
10 : 5
(÷5)
2 : 1
The total number of oranges and persimmons is repeated. Make the total number of oranges and persimmons the same. LCM of 3 and 4 is 12.
Number of more pomegranates than persimmons
= 9 u - 4 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of the fruits in the box altogether
= 8 u + 4 u + 9 u
= 21 u
= 21 x 12
= 252
Answer(s): 252