A container contains some pears, persimmons and lemons. 0.2 of the pears is equal to 70% of the persimmons. The number of lemons is ¹₂ of the total number of persimmons and pears. If there are 60 less persimmons than lemons, how many fruits are there in the container altogether?

Pears	Persimmons	Lemons
7x2	2x2
2x9		1x9
14 u	4 u	9 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the pears is equal to 70% of the persimmons. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the pears = 7x110x1 of the persimmons
735 of the pears = 710 of the persimmons 

Pears : Persimmons
35 : 10 _(÷5)
7 : 2

The total number of pears and persimmons is repeated.  Make the total number of pears and persimmons the same.  LCM of 9 and 2 is 18.

Number of less persimmons than lemons
= 9 u - 4 u
= 5 u

5 u = 60

1 u = 60 ÷ 5 = 12

Number of the fruits in the container altogether
= 14 u + 4 u + 9 u
= 27 u
= 27 x 12
= 324

Answer(s): 324