A container contains some persimmons, kiwis and apples. 0.4 of the persimmons is equal to 70% of the kiwis. The number of apples is ³₄ of the total number of kiwis and persimmons. If there are 34 more apples than kiwis, how many fruits are there in the container altogether?

Persimmons	Kiwis	Apples
7x4	4x4
4x11		3x11
28 u	16 u	33 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the persimmons is equal to 70% of the kiwis. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the persimmons = 7x210x2 of the kiwis
1435 of the persimmons = 1420 of the kiwis 

Persimmons : Kiwis
35 : 20 _(÷5)
7 : 4

The total number of persimmons and kiwis is repeated.  Make the total number of persimmons and kiwis the same.  LCM of 11 and 4 is 44.

Number of more apples than kiwis
= 33 u - 16 u
= 17 u

17 u = 34

1 u = 34 ÷ 17 = 2

Number of the fruits in the container altogether
= 28 u + 16 u + 33 u
= 77 u
= 77 x 2
= 154

Answer(s): 154