Gillian, Xuan and Irene had a total of 589 coins. Gillian gave
49 of her coins away. Irene gave away 5 times as many coins as Gillian and Xuan gave away 47 coins. In the end, they had 110 coins left. How many coins did Xuan and Irene have in total in the end?
|
Gillian |
Xuan |
Irene |
Total |
Before |
9 u |
? |
? |
589 |
Change |
- 4 u |
- 47 |
- 20 u |
- 479 |
After |
5 u |
? |
110 |
Number of coins that Irene gave away
= 5 x 4 u
= 20 u
Number of coins given away
= 4 u + 47 + 20 u
= 24 u + 47
24 u + 47 = 589 - 110
24 u = 479 - 47
24 u = 432
1 u = 432 ÷ 24 = 18
Number of coins that Xuan and Irene had in the end
= 110 - 5 u
= 110 - 5 x 18
= 110 - 90
= 20
Answer(s): 20