Xuan, Gabby and Hilda had a total of 202 coins. Xuan gave
110 of her coins away. Hilda gave away 3 times as many coins as Xuan and Gabby gave away 83 coins. In the end, they had 103 coins left. How many coins did Gabby and Hilda have in total in the end?
| |
Xuan |
Gabby |
Hilda |
Total |
| Before |
10 u |
? |
? |
202 |
| Change |
- 1 u |
- 83 |
- 3 u |
- 99 |
| After |
9 u |
? |
103 |
Number of coins that Hilda gave away
= 3 x 1 u
= 3 u
Number of coins given away
= 1 u + 83 + 3 u
= 4 u + 83
4 u + 83 = 202 - 103
4 u = 99 - 83
4 u = 16
1 u = 16 ÷ 4 = 4
Number of coins that Gabby and Hilda had in the end
= 103 - 9 u
= 103 - 9 x 4
= 103 - 36
= 67
Answer(s): 67
