Three cartons, C, A and B, contained 138 marbles. Perry added some marbles into Carton C and the number of marbles in Carton C tripled. He took out half of the number of marbles from Carton A and added another 27 marbles into Carton B. As a result, the ratio of the number of marbles in Carton C, Carton A and Carton B became 12 : 4 : 3. What was the ratio of the number of marbles in Carton A to the total number of marbles in Carton C and Carton B at first? Give the answer in its lowest term.
|
Carton C |
Carton A |
Carton B |
Total |
Before |
1x4 = 4 u |
2x4 = 8 u |
3 u - 27 |
138 |
Change |
+ 2x4 = + 8 u |
- 1x4 = - 4 u |
+ 27 |
|
After |
3x4 = 12 u |
1x4 = 4 u |
|
|
Comparing the 3 cartons |
12 u |
4 u |
3 u |
|
The number of marbles in Carton C in the end is repeated. Make the number of marbles in Carton C in the end the same. LCM of 3 and 12 is 12.
The number of marbles in Carton A in the end is repeated. Make the number of marbles in Carton A in the end the same. LCM of 1 and 4 is 4.
Total number of marbles at first
= 4 u + 8 u + 3 u - 27
= 15 u - 27
15 u - 27 = 138
15 u = 138 + 27
15 u = 165
1 u = 165 ÷ 15 = 11
Number of marbles in Carton A at first
= 8 u
= 8 x 11
= 88
Number of marbles in Carton C and Carton B at first
= 138 - 88
= 50
Carton A : Carton C and Carton B
88 : 50
(÷2)44 : 25
Answer(s): 44 : 25