The total volume of water in Tank L, Tank M and Tank N was 183 mℓ. Ian poured out half the volume of water from Tank L, doubled the amount of water in Tank M and added 123 mℓ of water into Tank N. The ratio of the volume of water in Tank L to Tank M to Tank N is now 4 : 10 : 5. Find the total volume of water in the three tanks now.
|
L |
M |
N |
Before |
8 u |
5 u |
5 u - 123 |
Change |
- 4 u |
+ 5 u |
+ 123 |
After |
4 u |
10 u |
5 u |
Volume of water in Tank L at first before Tommy poured out half the volume
= 2 x 4 u
= 8 u
Volume of water in Tank M at first before Tommy doubled the volume
= 10 u ÷ 2
= 5 u
Volume of water in Tank M at first before Tommy added 123 mℓ of water
= 5 u - 123
Total volume of water in the three tanks at first
= 8 u + 5 u + 5 u - 123
= 18 u - 123
18 u - 123 = 183
18 u = 183 + 123
18 u = 306
1 u = 306 ÷ 18 = 17
Total volume of water in the three tanks now
= 4 u + 10 u + 5 u
= 19 u
= 19 x 17
= 323 mℓ
Answer(s): 323 mℓ