The total volume of water in Tank S, Tank T and Tank U was 348 mℓ. Ian poured out half the volume of water from Tank S, tripled the amount of water in Tank T and poured out 128 mℓ of water from Tank U. The ratio of the volume of water in Tank S to Tank T to Tank U is now 2 : 3 : 6. Find the total volume of water in the three tanks now.
| |
S |
T |
U |
| Before |
4 u |
1 u |
6 u + 128 |
| Change |
- 2 u |
+ 2 u |
- 128 |
| After |
2 u |
3 u |
6 u |
Volume of water in Tank S at first before Simon poured out half the volume
= 2 x 2 u
= 4 u
Volume of water in Tank T at first before Simon tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Tank T at first before Simon poured out 128 mℓ of water
= 6 u + 128
Total volume of water in the three tanks at first
= 4 u + 1 u + 6 u + 128
= 11 u + 128
11 u + 128 = 348
11 u = 348 - 128
11 u = 220
1 u = 220 ÷ 11 = 20
Total volume of water in the three tanks now
= 2 u + 3 u + 6 u
= 11 u
= 11 x 20
= 220 mℓ
Answer(s): 220 mℓ
