The total volume of water in Watering Can P, Watering Can Q and Watering Can R was 392 mℓ. Ian poured out half the volume of water from Watering Can P, doubled the amount of water in Watering Can Q and added 88 mℓ of water into Watering Can R. The ratio of the volume of water in Watering Can P to Watering Can Q to Watering Can R is now 9 : 4 : 4. Find the total volume of water in the three watering cans now.
| |
P |
Q |
R |
| Before |
18 u |
2 u |
4 u - 88 |
| Change |
- 9 u |
+ 2 u |
+ 88 |
| After |
9 u |
4 u |
4 u |
Volume of water in Watering Can P at first before Eric poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Watering Can Q at first before Eric doubled the volume
= 4 u ÷ 2
= 2 u
Volume of water in Watering Can Q at first before Eric added 88 mℓ of water
= 4 u - 88
Total volume of water in the three watering cans at first
= 18 u + 2 u + 4 u - 88
= 24 u - 88
24 u - 88 = 392
24 u = 392 + 88
24 u = 480
1 u = 480 ÷ 24 = 20
Total volume of water in the three watering cans now
= 9 u + 4 u + 4 u
= 17 u
= 17 x 20
= 340 mℓ
Answer(s): 340 mℓ
