The total volume of water in Watering Can P, Watering Can Q and Watering Can R was 10 mℓ. Ian poured out half the volume of water from Watering Can P, doubled the amount of water in Watering Can Q and added 81 mℓ of water into Watering Can R. The ratio of the volume of water in Watering Can P to Watering Can Q to Watering Can R is now 3 : 8 : 3. Find the total volume of water in the three watering cans now.
| |
P |
Q |
R |
| Before |
6 u |
4 u |
3 u - 81 |
| Change |
- 3 u |
+ 4 u |
+ 81 |
| After |
3 u |
8 u |
3 u |
Volume of water in Watering Can P at first before Bryan poured out half the volume
= 2 x 3 u
= 6 u
Volume of water in Watering Can Q at first before Bryan doubled the volume
= 8 u ÷ 2
= 4 u
Volume of water in Watering Can Q at first before Bryan added 81 mℓ of water
= 3 u - 81
Total volume of water in the three watering cans at first
= 6 u + 4 u + 3 u - 81
= 13 u - 81
13 u - 81 = 10
13 u = 10 + 81
13 u = 91
1 u = 91 ÷ 13 = 7
Total volume of water in the three watering cans now
= 3 u + 8 u + 3 u
= 14 u
= 14 x 7
= 98 mℓ
Answer(s): 98 mℓ
