The total volume of water in Tank S, Tank T and Tank U was 233 mℓ. Ian poured out half the volume of water from Tank S, tripled the amount of water in Tank T and poured out 73 mℓ of water from Tank U. The ratio of the volume of water in Tank S to Tank T to Tank U is now 2 : 3 : 5. Find the total volume of water in the three tanks now.
|
S |
T |
U |
Before |
4 u |
1 u |
5 u + 73 |
Change |
- 2 u |
+ 2 u |
- 73 |
After |
2 u |
3 u |
5 u |
Volume of water in Tank S at first before Henry poured out half the volume
= 2 x 2 u
= 4 u
Volume of water in Tank T at first before Henry tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Tank T at first before Henry poured out 73 mℓ of water
= 5 u + 73
Total volume of water in the three tanks at first
= 4 u + 1 u + 5 u + 73
= 10 u + 73
10 u + 73 = 233
10 u = 233 - 73
10 u = 160
1 u = 160 ÷ 10 = 16
Total volume of water in the three tanks now
= 2 u + 3 u + 5 u
= 10 u
= 10 x 16
= 160 mℓ
Answer(s): 160 mℓ