The total volume of water in Tank P, Tank Q and Tank R was 179 mℓ. Ian poured out half the volume of water from Tank P, tripled the amount of water in Tank Q and poured out 111 mℓ of water from Tank R. The ratio of the volume of water in Tank P to Tank Q to Tank R is now 1 : 3 : 1. Find the total volume of water in the three tanks now.
|
P |
Q |
R |
Before |
2 u |
1 u |
1 u + 111 |
Change |
- 1 u |
+ 2 u |
- 111 |
After |
1 u |
3 u |
1 u |
Volume of water in Tank P at first before Brandon poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Tank Q at first before Brandon tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Tank Q at first before Brandon poured out 111 mℓ of water
= 1 u + 111
Total volume of water in the three tanks at first
= 2 u + 1 u + 1 u + 111
= 4 u + 111
4 u + 111 = 179
4 u = 179 - 111
4 u = 68
1 u = 68 ÷ 4 = 17
Total volume of water in the three tanks now
= 1 u + 3 u + 1 u
= 5 u
= 5 x 17
= 85 mℓ
Answer(s): 85 mℓ