The total volume of water in Tank M, Tank N and Tank P was 433 mℓ. Ian poured out half the volume of water from Tank M, tripled the amount of water in Tank N and poured out 118 mℓ of water from Tank P. The ratio of the volume of water in Tank M to Tank N to Tank P is now 4 : 9 : 10. Find the total volume of water in the three tanks now.
|
M |
N |
P |
Before |
8 u |
3 u |
10 u + 118 |
Change |
- 4 u |
+ 6 u |
- 118 |
After |
4 u |
9 u |
10 u |
Volume of water in Tank M at first before David poured out half the volume
= 2 x 4 u
= 8 u
Volume of water in Tank N at first before David tripled the volume
= 9 u ÷ 3
= 3 u
Volume of water in Tank N at first before David poured out 118 mℓ of water
= 10 u + 118
Total volume of water in the three tanks at first
= 8 u + 3 u + 10 u + 118
= 21 u + 118
21 u + 118 = 433
21 u = 433 - 118
21 u = 315
1 u = 315 ÷ 21 = 15
Total volume of water in the three tanks now
= 4 u + 9 u + 10 u
= 23 u
= 23 x 15
= 345 mℓ
Answer(s): 345 mℓ