The total volume of water in Bottle R, Bottle S and Bottle T was 389 mℓ. Ian poured out half the volume of water from Bottle R, tripled the amount of water in Bottle S and poured out 133 mℓ of water from Bottle T. The ratio of the volume of water in Bottle R to Bottle S to Bottle T is now 5 : 9 : 3. Find the total volume of water in the three bottles now.
| |
R |
S |
T |
| Before |
10 u |
3 u |
3 u + 133 |
| Change |
- 5 u |
+ 6 u |
- 133 |
| After |
5 u |
9 u |
3 u |
Volume of water in Bottle R at first before Xavier poured out half the volume
= 2 x 5 u
= 10 u
Volume of water in Bottle S at first before Xavier tripled the volume
= 9 u ÷ 3
= 3 u
Volume of water in Bottle S at first before Xavier poured out 133 mℓ of water
= 3 u + 133
Total volume of water in the three bottles at first
= 10 u + 3 u + 3 u + 133
= 16 u + 133
16 u + 133 = 389
16 u = 389 - 133
16 u = 256
1 u = 256 ÷ 16 = 16
Total volume of water in the three bottles now
= 5 u + 9 u + 3 u
= 17 u
= 17 x 16
= 272 mℓ
Answer(s): 272 mℓ
