The total volume of water in Tank Q, Tank R and Tank S was 190 mℓ. Ian poured out half the volume of water from Tank Q, doubled the amount of water in Tank R and added 53 mℓ of water into Tank S. The ratio of the volume of water in Tank Q to Tank R to Tank S is now 9 : 4 : 7. Find the total volume of water in the three tanks now.
| |
Q |
R |
S |
| Before |
18 u |
2 u |
7 u - 53 |
| Change |
- 9 u |
+ 2 u |
+ 53 |
| After |
9 u |
4 u |
7 u |
Volume of water in Tank Q at first before Howard poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Tank R at first before Howard doubled the volume
= 4 u ÷ 2
= 2 u
Volume of water in Tank R at first before Howard added 53 mℓ of water
= 7 u - 53
Total volume of water in the three tanks at first
= 18 u + 2 u + 7 u - 53
= 27 u - 53
27 u - 53 = 190
27 u = 190 + 53
27 u = 243
1 u = 243 ÷ 27 = 9
Total volume of water in the three tanks now
= 9 u + 4 u + 7 u
= 20 u
= 20 x 9
= 180 mℓ
Answer(s): 180 mℓ
