The total volume of water in Tank M, Tank N and Tank P was 345 mℓ. Ian poured out half the volume of water from Tank M, tripled the amount of water in Tank N and poured out 135 mℓ of water from Tank P. The ratio of the volume of water in Tank M to Tank N to Tank P is now 3 : 6 : 7. Find the total volume of water in the three tanks now.
|
M |
N |
P |
Before |
6 u |
2 u |
7 u + 135 |
Change |
- 3 u |
+ 4 u |
- 135 |
After |
3 u |
6 u |
7 u |
Volume of water in Tank M at first before Oscar poured out half the volume
= 2 x 3 u
= 6 u
Volume of water in Tank N at first before Oscar tripled the volume
= 6 u ÷ 3
= 2 u
Volume of water in Tank N at first before Oscar poured out 135 mℓ of water
= 7 u + 135
Total volume of water in the three tanks at first
= 6 u + 2 u + 7 u + 135
= 15 u + 135
15 u + 135 = 345
15 u = 345 - 135
15 u = 210
1 u = 210 ÷ 15 = 14
Total volume of water in the three tanks now
= 3 u + 6 u + 7 u
= 16 u
= 16 x 14
= 224 mℓ
Answer(s): 224 mℓ