The total volume of water in Watering Can S, Watering Can T and Watering Can U was 217 mℓ. Ian poured out half the volume of water from Watering Can S, tripled the amount of water in Watering Can T and poured out 100 mℓ of water from Watering Can U. The ratio of the volume of water in Watering Can S to Watering Can T to Watering Can U is now 1 : 3 : 6. Find the total volume of water in the three watering cans now.
| |
S |
T |
U |
| Before |
2 u |
1 u |
6 u + 100 |
| Change |
- 1 u |
+ 2 u |
- 100 |
| After |
1 u |
3 u |
6 u |
Volume of water in Watering Can S at first before Riordan poured out half the volume
= 2 x 1 u
= 2 u
Volume of water in Watering Can T at first before Riordan tripled the volume
= 3 u ÷ 3
= 1 u
Volume of water in Watering Can T at first before Riordan poured out 100 mℓ of water
= 6 u + 100
Total volume of water in the three watering cans at first
= 2 u + 1 u + 6 u + 100
= 9 u + 100
9 u + 100 = 217
9 u = 217 - 100
9 u = 117
1 u = 117 ÷ 9 = 13
Total volume of water in the three watering cans now
= 1 u + 3 u + 6 u
= 10 u
= 10 x 13
= 130 mℓ
Answer(s): 130 mℓ
