The total volume of water in Watering Can M, Watering Can N and Watering Can P was 368 mℓ. Ian poured out half the volume of water from Watering Can M, doubled the amount of water in Watering Can N and added 64 mℓ of water into Watering Can P. The ratio of the volume of water in Watering Can M to Watering Can N to Watering Can P is now 9 : 2 : 8. Find the total volume of water in the three watering cans now.
| |
M |
N |
P |
| Before |
18 u |
1 u |
8 u - 64 |
| Change |
- 9 u |
+ 1 u |
+ 64 |
| After |
9 u |
2 u |
8 u |
Volume of water in Watering Can M at first before Bobby poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Watering Can N at first before Bobby doubled the volume
= 2 u ÷ 2
= 1 u
Volume of water in Watering Can N at first before Bobby added 64 mℓ of water
= 8 u - 64
Total volume of water in the three watering cans at first
= 18 u + 1 u + 8 u - 64
= 27 u - 64
27 u - 64 = 368
27 u = 368 + 64
27 u = 432
1 u = 432 ÷ 27 = 16
Total volume of water in the three watering cans now
= 9 u + 2 u + 8 u
= 19 u
= 19 x 16
= 304 mℓ
Answer(s): 304 mℓ
