The total volume of water in Tank S, Tank T and Tank U was 36 mℓ. Ian poured out half the volume of water from Tank S, doubled the amount of water in Tank T and added 64 mℓ of water into Tank U. The ratio of the volume of water in Tank S to Tank T to Tank U is now 8 : 6 : 1. Find the total volume of water in the three tanks now.
| |
S |
T |
U |
| Before |
16 u |
3 u |
1 u - 64 |
| Change |
- 8 u |
+ 3 u |
+ 64 |
| After |
8 u |
6 u |
1 u |
Volume of water in Tank S at first before Ben poured out half the volume
= 2 x 8 u
= 16 u
Volume of water in Tank T at first before Ben doubled the volume
= 6 u ÷ 2
= 3 u
Volume of water in Tank T at first before Ben added 64 mℓ of water
= 1 u - 64
Total volume of water in the three tanks at first
= 16 u + 3 u + 1 u - 64
= 20 u - 64
20 u - 64 = 36
20 u = 36 + 64
20 u = 100
1 u = 100 ÷ 20 = 5
Total volume of water in the three tanks now
= 8 u + 6 u + 1 u
= 15 u
= 15 x 5
= 75 mℓ
Answer(s): 75 mℓ
